__Directions: __Following Pie charts represent the number of students, who have appeared and cleared phase I of Civil Service Exam from various departments of an Arts and Science College.

**1. Approximately what is the difference between the number of students cleared phase I from Maths department and number of students appeared from English department? **

A.1350

B. 1240

C. 1340

D. 1250

E. None of these

**2. The total number of students clearing phase I from commerce and other department is what percentage of the number of students clearing phase I from physics department? **

A.340 %

B. 310 %

C. 320 %

D. 330 %

E. None of these

**3. What has the ratio between numbers of students appeared from Maths and physics departments to the number of students appeared from chemistry and commerce departments? **

A.16:15

B. 15:17

C. 16:17

D. 15:16

E. None of these

**4. From which department is the difference between the number of students cleared and the number of students appeared is the second minimum? **

A. Chemistry

B. Physics

C. Commerce

D. Maths

E. None of these

**5. What is the percentage of students, who did not clear the phase I of the exam? **

A. 84.45%

B. 84.55%

C.83.55%

D.83.45%

E. None of these

View Solution

#### Solutions:

#### 1. Option C

→ No. of students cleared from Maths department = (60/360) * 847 = 141

→ No. of students appeared from English department = (27/ 100)* 5484 ≈ 1481

→ Difference = 1481-141 = 1340 (ans)

#### 2. Option D

→ No. of students cleared from commerce & other dept. = [(72+67) /360]*847 = (139/360)* 847 = 327

→ No. of students cleared physics department = (42/360)* 847 = 99

→ X= (327/99)* 100

→ X= 330 % (ans)

#### 3. Option C

→ Ratio = (Maths +Physics): (Chemistry + Commerce) = (18+14): (11+23) = 32: 34 = 16:17 (ans)

#### 4. Option A

__English Department: __

→ Appeared = (27/100) * 5484 = 1481

→ Cleared = (88/360)* 847=207

→ Difference = (1485-207) = 1274

__Maths Department: __

→ Appeared = (18/100) * 5484 = 987

→ Cleared = (60/360)* 847=141

→ Difference = (987-141) = 846

__Physics Department: __

→ Appeared = (14/100) * 5484 = 768

→ Cleared = (42/360)* 847=99

→ Difference = (768-99) = 669

__Chemistry Department:__

→ Appeared = (11/100) * 5484 = 603

→ Cleared = (31/360)* 847= 73

→ Difference = (603-73) = 530 (ans)

__Commerce Department: __

→ Appeared = (23/100) * 5484 = 1261

→ Cleared = (72/360)* 847= 169

→ Difference = (1261-169) = 1092

__Other Departments: __

→ Appeared = (7/100) * 5484 = 384

→ Cleared = (67/360)* 847= 158

→ Difference = (384-158) =226

#### 5. Option B

→ No. of students not cleared= (5484 -847) = 4637

→ % of students not cleared = (4637/5484) *100 = 84.55 % (ans)

**Directions (6-9): Study the following information carefully and answer the given questions.**

In the recently held elections there were 5000 voters in a constituency. Out of those, 1450 voted only for the BJP, 1050 voted only for the AAP and 950 voted only for the Congress. The number of voters voting for all the parties is 625. The number of voters voting for the BJP and the Congress is 235. The number of voters who voted for the AAP and the Congress is 115 and those who voted for the AAP and the BJP is 425.

**Note: **A voter can vote for any number of parties.

**6. How many voters voted for at least two parties?**

1) 1200 2) 775 3) 1300

4) 1400 5) 1050

**7.. Find the numbers of voters who voted for the BJP.**

1) 2735 2) 2745 3) 2800

4) 2700 5) None of these

**8. How many voters voted for only one party?**

1) 3300 2) 3350 3) 3600 4) 3400 5) 3450

**9. How many voters did not vote for any party?**

1) 200 2) 350 3) 150

4) 400 5) 250

**10. A contractor undertakes to complete a work in 25 days. He employs 27 labourers on this job but after 16 days he finds that only half of the work has been done. How many more labourers should he employ to complete the work in time?**

1) 18 2) 21 3) 27

4) 25 5) 14

View Answers

6. 4; People who voted for two parties = 425 + 625 + 235 + 115 = 1400

7. 1; Number of voters who voted for the BJP = (1450 + 235 + 625 + 425) = 2735

8. 5; People who voted for only one party = (1450 + 1050 + 950) = 3450

9. 3; People who did not vote for any party = 5000 – (1450 + 950 + 1050 + 425 + 625 + 115 + 235) = 5000 – (4850) = 150

10. 2; Remaining part of the work = x/2

Remaining number of days = 25 – 16 = 9 days

Hence, 9 × x = 16 × 27

x =16*27/ 9 = 48

So, the number of more labourers reqd = 48 – 27 = 21